The probability of 16 randomly selected packages will have a weight in excess of 16.065 ounces can be calculated using the normal distribution formula. The mean weight of the sugar bags is 16 ounces and the standard deviation is 0.2 ounces, so we can calculate the z-score for 16.065 ounces by subtracting the mean (16 ounces) from it and dividing this difference (0.065) by the standard deviation (0.2). This gives us a z-score of 0.325 which corresponds to a probability value of 0.6374 or 63.74%.
Packages of sugar bags for Sweeter Sugar Inc. have an average weight of 16 ounces and a standard deviation of 0.2 ounces. The weights of the sugar bags are normally distributed. What is the probability that 16 randomly selected packages will have a weight in excess of 16.065 ounces?
This means that out of 16 randomly selected packages, there is a 63.74% chance that at least one package will have a weight of more than 16.065 ounces and 36.26% chance that none will have such a weight value greater than this amount according to normal distribution formula for probability calculations with given parameters “mean” and “standard deviation”.